Scribe Post. Bekah. Parallel Lines & Review(chapter 1, 2, 3) 9/14/09 & 9/15/09.

Hey guys.
This scribe is for yesterday(9/14/09) and today(9/15/09)
Yesterday we had our Daily Quiz #9, which was figuring out the measurement of an acute angle, when given certain information. We got our Daily Quiz # 8 back. Jojo explained it to us. In this Daily Quiz we had to draw a geometric figure that had a vertical angle, corresponding angle, supplementary angle, alternate interior angle and alternate exterior angle. Jojo showed us an easy we of drawing a neat figure. This was giving a letter to each line and intersection rather then to all the different angles. This made a more organized geometric figure diagram and made it easier to find all of the different angles we had to find out. After we went over that, we started going over the Parallel Lines handout. Most people understand problems 1, 2, 3 and 4. Number 5 somewhat tricky to some people though. The question gives us a geometric figure of what looks like to be two sets of parallel lines. It also gives us 11 facts, 7 of which or telling us which angles are congruent to each other and 3 telling us which angles are supplementary to each other. The problem wants us to use this information to figure out which lines are parallel, if any and then explain what enables us to prove that the lines are parallel. 5c. says that angle 3 is congruent to angle 2. If this were correct then the two sets of parallel lines are not parallel. Then the topic that all the different facts on congruent and supplementary angles are different problems therefor c was the only answer that says that the lines are not parallel. We also went over problem 6 which has two angles made out of four two sets of parallel lines. (line AB is parallel to CD, and line BC is parallel to line DE) and we must explain why angle B is congruent to angle D. The reason to this is because angle C and angle D are alternate exterior angles. This also means that angle B and angle D would have to be congruent, too.
That pretty much sums up our Monday.

Today, 9/15/09 we got our Daily Quiz #9 back. We went over how to get the answer when we are trying to find the acute angle of line when the obtuse angle is three times as big as the acute angle. In this problem you would make the equation x + 3x = 180 and solve, or you could use x + x + 3x + 3x = 180. Solve that and then divide x by 2. We then finished going over the Parallel Lines handout. A lot of people had a difficult time on the last two problems, 7 and 8. In 7 we found out that we were dealing with perimeter, which we need to know for the test. A perimeter is the sum of the lengths of all sides. We had to figure out what the perimeter was for triangle KNM, when given this information: JO is parallel to line KN. Line JK is parallel to line ON. Line JO is congruent to line KM. Line JO = 3x + 4, line KN = 2x + 7 and line MN = 6. Since we are trying to find the perimeter of triangle KNM we we need to figure out the lengths of line KN and line KM. (We already know the length for MN is 6.) From the information given we know that JO is congruent to KM. We also know that JO is parallel to KN and since JK and ON are also parallel then JO and KN must equal the same length, which also means that KN and KM equal the same length. So the next thing to do is set up our equation. 2x + 7 = 3x + 4. This shows us that x is equal to 3. We plug 3 into both of the equations 2(3) + 7 which = 13 and we already know that lines KN and KM are the same so they both equal 13. Then we add them all up: 13 +13 +6 = 32 unites. Problem 8 was probably the hardest of them all. There are two problems, both very similar. for the first one we are given two parallel lines with an angle in between them. The angle is an acute angle that makes a 160 degree angle on the top line and a 40 degree angle on the bottom line (looking at the problem when reading this will really help you understand what i am saying.) We need to figure out what the angle is. The way we figure this out was making transversals for the angle. Once we have made the transversals we can figure out that on the top triangle (which was made by the transversals) 20 degrees makes one of the angles, because we know that a line = 180 degrees and we have 160 degrees on the opposite side of the angle. Since we know that wear the angle hits the bottom parallel line it is 40 degrees. In the triangle that has the angle 20 degrees we know that the 40 degrees is an alternate exterior to the second degree of the top triangle. These measurements give us 60 degrees. A triangle = 180 degrees so we subtract 60 degrees from 180 degrees and get 120 degrees. The angle we need to figure out is on this line that is 120 degrees, so we subtract 120 degrees from 180 degrees and we get 60 degrees. So the angle is 60 degrees. In the second problem you pretty much do the exact same thing. Make the transversals and figure out the alternate interior, exterior and complemmentary angles. We then went over all of our homework and past problems in the class to see if anyone had any more questions before the test. No one had any though.
That was our day. Good luck on the test tomorrow.
For the next scribe i pick...isabel.