Wednesday, September 30, 2009
Scribe Post - Miranda, Chapter 5
Scribe Post for Sept. 30
Hey everyone, today in class we started out by taking daily quiz #14.
- Daily quiz #14 was focused on finding the measures of unknown angles of certain triangles when given one angle. For example: If triangle ABC is isosceles, and angle A is 80 degrees, what are the other possible measures of angle B?
o To solve this problem we must first think about the information already given. We know that a - the triangle is isosceles (deff. of isosceles triangle: a triangle with two sides/angles equal in length/measure) and b – one of the angles measures 80 degrees.
o There are three possible answers to this problem.
o We can start with the most obvious – since two angles in an isosceles triangle are equal in measure, A=B so B=80 degrees.
o The second way to find the measure of B is to assume A=C. So, A + B + C = 180, therefore 80 + 80 + B = 180. When solved algebraically, the answer is B=20 degrees.
o The final way to find the measure of B is assume that B=C. This equation looks like
80 + B + C = 180. Solved algebraically, B and C both equal 50 degrees.
After taking daily quiz #14 we went over daily quiz #13.
- We discussed finding the answer to the “longest side, shortest side, middle side” problem using the “small parts equal whole parts” method.
- JoJo made a point that just trying to use common sense to find the answer to a problem doesn’t always work.
More info. on the Flickr project:
- It takes a few days for photos to show up on a search after they are uploaded
- The deadline for the Flickr project was pushed back to Friday
- Hopefully everyone has already uploaded/made a Flickr! If not, here is the link: http://www.flickr.com/
Lesson-
The main lesson consisted of JoJo discussing (or preaching…) about the difference between rotation, length and area.
- Rotation: rotation deals with the measure of angles.
- Length: used when measuring the length in units like inches or feet.
- Area: deals with space. Area is used to find how big a plane is using square feet.
We traced our hands on graph paper to demonstrate how difficult it is to find area with no equation. (counting the "little squares" was impossible.
Here are some helpful sights when dealing with area:
http://www.purplemath.com/modules/geoform.htm (this site goes on to talk about volume which we haven’t reached yet, but it has useful information about the different formulas to find the area of different shapes)
http://www.mathleague.com/help/geometry/area.htm (this site consists of formulas to find the areas of different shapes.)
I hope all of this was helpful.
Tomorrow’s scribe is McKenzie.
*note
if the links don't work, purplemath.com is a great site for extra help. If you search "area" all sorts of help pages will come up and you can go from there.
(please excuse the lateness of this post...busy night with lots of work...)
Tuesday, September 29, 2009
Scribe Post- Jocelyn-Chapter Four
Hey GUYS this is what we did today!!
1. We took DQ 13 on Triangles
2. We went over DQ 12 (Which was the same one our parents did on parents night!)
* Sum of Interior Angles of a Polygon= 180 (n-2)
. the (n-2) is the minium number of inscribed traingles.
. and the n is the sides of a polygon
A. 360= 180 (4-2)
180(2)=360 degrees
B. Hexagon= 180 (6-2)
180(4)=720 degrees
C. Octagon= 180 (8-2)
180(6)=1,080 degrees
Jojo said in our class that this is very important and practical. Like in the case if you were building something!!
3. Went over the Flickr assignment
* If you are having trouble posting, you need to have over five pictures on your account for it to show up under the tabs, also make sure you properly tabs your pictures to receive credit tomorrow!!!!
4. Looked at google docs to see if we got credit for both contributions.
* Make sure if you are trying to get a signicant contribution on a homework problem to show all your work!!!
*Show Work always
I hope some of this was helpful! Tomorrow's scribe is Miranda
Have a Good Night Everyone and I will see you tomorrow!!!
Thursday, September 24, 2009
Scribe Post, Charles Bennett, Chapters 4 & 5
After we had admired our work for a little bit Jojo then asked us if we knew how many line segments there were inside of our circle. After many failed attempts to answer the question Jojo then gave us the formula we needed to find out how many interior angles were inside of the circle.
The sum of interior angles= 180(n-2)
If you look at the Polygon Table On PBworks then you would find the pattern that is shown within the table. Every polygon's # of inscribed triangles is two less than the amount of its # of sides. In the formula the n represents the # of sides on a polygon.
Then we created another star in the second circle this time we were not allowed to intersect the lines. This was proven difficult so instead we just created the star how we did the first time and erased the parts where the line was intersected.
Then we did problem #19 in Chapter 4 on pg 56 in our math workbook. The problem states
"In a certain isosceles triangle, the smallest angle has a measure of 28 degrees. What are the measures of the two largest angles?" While answering this problem we kept in mind the new tip about dealing with isosceles triangles,
"When solving isosceles triangles we can assume three different scenarios will occur unless the given angle is stated as a the smallest or the largest. Then there is only one possible answer for the missing angles."
When solving this problem we knew that Isosceles triangles have at least two sides and that we already have a side given that states that it is the smallest angle, therefore we know the other two sides of this triangle are equal. Thus, we are able to say both variables in place for the missing measurements can be expressed as x=y
When we set up our problem we were also able to use to x's in our eqaution because x=y.
First step- 28+x+x=180
We set up the problem like this because we know that all sides of a triangle equal 180 therefore we must set our variables and our given measurment equal to 180.
Second step- 2x=152
We must had like terms and subtract 28 from both sides.
Third Step (solve)- x=76
Today's SCRIBE IS JERICHOOOO!!!
Tuesday, September 22, 2009
Scribe Post, Andrew Braden, Ch.4 and 5 Polygons
Altitude- is a perpendicular segment that joins a vertex of a triangle to the opposite side.
Right Triangle- a right triangle is a triangle where one of its interior angles is a right angle.
Obtuse Triangle- An obtuse triangle is a triangle in which one of the angles is an obtuse angle.
Acute Triangle- An acute triangle is a triangle in which all three angles are acute angles.
Isosceles Triangle- An isosceles triangle is a triangle with two equal sides.
IF you are given one angle in an isosceles triangle you can find three possibilities for the other two angles using big parts equals small parts. You also know that two angles must always be the same.
If you are given
Then your possibilities are
I am going to choose Charles for tommorrows scribe.
Monday, September 21, 2009
Scribe Post-Tom-ch.4 and ch. 5 Polygons
Sunday, September 20, 2009
Scribe Post. Isabel. Ch. 4 and Ch. 5 Polygons. Unit 2
Today we talked about the “BoB”, or “Blogging on Blogging”, comments on the blog. Jojo read aloud some of the comments which he thought were good feedback about the blog and we discussed how we could improve our class blog. Jojo is working on simplifying the blog and making it easier to use!
We began the next unit (This means that all blog point’s- comments, PoPs, ect. - grading will start over. So make sure you begin to get credit for blogging on this unit!). This new unit covers chapter 4 – polygons, and chapter 5- area.
Chapter 4- Polygons:
(Our text book's definition of a polygon) Polygon- is a geometric figure that consists of three or more line segments joined end-to-end so as to enclose a region of the plane that contains those segments. Each corner of a polygon is called a vertex (plural is “vertices”). The line segments which form the polygon are called sides.
A simpler definition of a polygon (from dictionary.com)- a closed figure having three or more sides and lying on one plane.
Jojo discussed polygons, “geometry is everywhere!”, and “polygons everywhere!” we looked at some very interesting videos about polygons. One of them was a video about polygon art; someone used a computer design program to use polygons to create an undersea scene. The link is below:
(View build- having fun- under the sea)
http://www.youtube.com/watch?v=EU4zgzNFk0k
We also visited a very interesting website which had some great videos of polygons. Here is the link to the website. I recommend exploring it!
http://demonstrations.wolfram.com/index.html
Some of the demonstrations we watched about polygons on this website were; six hexagons, whirling polygons, and polygon simplification.
Jojo talked about how polygons were everywhere; a prime example of this was GPS systems. With GPS systems, anyplace where you are can be represented by a polygon using a satellite. If a polygon contains a set of info, there’s a certain algorithm (algorithm- “a computerized series of events that happen at a certain time”) that represents your position and gives you the information for that position. As you move around, your longitude and latitude change, and you get new sets of information on your GPS.
This pretty much sums up Fridays math class. I tried to find a website about GPS systems and how they work but I couldn’t find a good one. If you find a good link about GPS systems and polygons, comment on this scribe post and let me know!
The next scribe is Brian.
-Isabel
Tuesday, September 15, 2009
Scribe Post. Bekah. Parallel Lines & Review(chapter 1, 2, 3) 9/14/09 & 9/15/09.
This scribe is for yesterday(9/14/09) and today(9/15/09)
Yesterday we had our Daily Quiz #9, which was figuring out the measurement of an acute angle, when given certain information. We got our Daily Quiz # 8 back. Jojo explained it to us. In this Daily Quiz we had to draw a geometric figure that had a vertical angle, corresponding angle, supplementary angle, alternate interior angle and alternate exterior angle. Jojo showed us an easy we of drawing a neat figure. This was giving a letter to each line and intersection rather then to all the different angles. This made a more organized geometric figure diagram and made it easier to find all of the different angles we had to find out. After we went over that, we started going over the Parallel Lines handout. Most people understand problems 1, 2, 3 and 4. Number 5 somewhat tricky to some people though. The question gives us a geometric figure of what looks like to be two sets of parallel lines. It also gives us 11 facts, 7 of which or telling us which angles are congruent to each other and 3 telling us which angles are supplementary to each other. The problem wants us to use this information to figure out which lines are parallel, if any and then explain what enables us to prove that the lines are parallel. 5c. says that angle 3 is congruent to angle 2. If this were correct then the two sets of parallel lines are not parallel. Then the topic that all the different facts on congruent and supplementary angles are different problems therefor c was the only answer that says that the lines are not parallel. We also went over problem 6 which has two angles made out of four two sets of parallel lines. (line AB is parallel to CD, and line BC is parallel to line DE) and we must explain why angle B is congruent to angle D. The reason to this is because angle C and angle D are alternate exterior angles. This also means that angle B and angle D would have to be congruent, too.
That pretty much sums up our Monday.
Today, 9/15/09 we got our Daily Quiz #9 back. We went over how to get the answer when we are trying to find the acute angle of line when the obtuse angle is three times as big as the acute angle. In this problem you would make the equation x + 3x = 180 and solve, or you could use x + x + 3x + 3x = 180. Solve that and then divide x by 2. We then finished going over the Parallel Lines handout. A lot of people had a difficult time on the last two problems, 7 and 8. In 7 we found out that we were dealing with perimeter, which we need to know for the test. A perimeter is the sum of the lengths of all sides. We had to figure out what the perimeter was for triangle KNM, when given this information: JO is parallel to line KN. Line JK is parallel to line ON. Line JO is congruent to line KM. Line JO = 3x + 4, line KN = 2x + 7 and line MN = 6. Since we are trying to find the perimeter of triangle KNM we we need to figure out the lengths of line KN and line KM. (We already know the length for MN is 6.) From the information given we know that JO is congruent to KM. We also know that JO is parallel to KN and since JK and ON are also parallel then JO and KN must equal the same length, which also means that KN and KM equal the same length. So the next thing to do is set up our equation. 2x + 7 = 3x + 4. This shows us that x is equal to 3. We plug 3 into both of the equations 2(3) + 7 which = 13 and we already know that lines KN and KM are the same so they both equal 13. Then we add them all up: 13 +13 +6 = 32 unites. Problem 8 was probably the hardest of them all. There are two problems, both very similar. for the first one we are given two parallel lines with an angle in between them. The angle is an acute angle that makes a 160 degree angle on the top line and a 40 degree angle on the bottom line (looking at the problem when reading this will really help you understand what i am saying.) We need to figure out what the angle is. The way we figure this out was making transversals for the angle. Once we have made the transversals we can figure out that on the top triangle (which was made by the transversals) 20 degrees makes one of the angles, because we know that a line = 180 degrees and we have 160 degrees on the opposite side of the angle. Since we know that wear the angle hits the bottom parallel line it is 40 degrees. In the triangle that has the angle 20 degrees we know that the 40 degrees is an alternate exterior to the second degree of the top triangle. These measurements give us 60 degrees. A triangle = 180 degrees so we subtract 60 degrees from 180 degrees and get 120 degrees. The angle we need to figure out is on this line that is 120 degrees, so we subtract 120 degrees from 180 degrees and we get 60 degrees. So the angle is 60 degrees. In the second problem you pretty much do the exact same thing. Make the transversals and figure out the alternate interior, exterior and complemmentary angles. We then went over all of our homework and past problems in the class to see if anyone had any more questions before the test. No one had any though.
That was our day. Good luck on the test tomorrow.
For the next scribe i pick...isabel.
Monday, September 14, 2009
Blogging on Blogging -Reflections -BoB Unit 1
I am going to offer you one bonus point on your test with completion of a simple assignment. I would like you to post your reflections on the material covered so far. Just comment on this post. To get that bonus on your test, the kind of post I'd like you to make should have one or more of these characteristics:
- A reflection on a particular class (like the first paragraph above-how did that class enhance your learning?).
- A reflective comment on your progress in the course.
- A comment on something that you've learned that you thought was "cool".
- A comment about something that you found very hard to understand but now you get it! Describe what sparked that "moment of clarity" and what it felt like.
- Have you come across something we discussed in class out there in the "real world" or another class? Describe the connection you made.
Friday, September 11, 2009
Scribe Post Marc Chapter 3 9/11/09
Geometric Figures Flickr Project Winners!
The Blog -PoP
What have been some of the helpful, interesting, challenging, practical, or other positive thoughts you have experienced using our class blog, pb works, and google docs?
What is another way the blog could be serviceable to enhance our learning?
Also, how much time per night are you spending on your math HW overall and on the blog, pb works, or google docs specifically?
Wednesday, September 9, 2009
scribe post. nigel s. chapter 2.
the scribe post song!!!!!!!
Yea buddy! rolling on some maths books, pencil turned up waiting on emma to do the next scribe post! AYYYYYEEEE!!!!! new rapper in town!!!!!! yuahhhhhh!!!!!!!!
Chapter 2 Angles & Their Measures
Dr. Math's Response to the Great Debate!
Sometimes when debating subjects in math, it is good to consult an expert or two....Her is what Dr. Math had to say about this debat.
http://mathforum.org/library/drmath/view/55067.html
In mathematics we usually separate angles into "angles of inclination" and "angles of rotation." If you use the basic ideas of geometry in a plane, an angle is the "opening" between two rays. This leads to the names above. But if we talk about angles greater than 360 degrees, this can not happen "between" two rays. I have never heard anyone give either of the names to angles greater than 360 because we almost always are talking about the rotation of an angle in terms of some reference or stationary ray. Perhaps a more important term would be the term used in expressing the idea you gave when you wrote "because when you draw an angle, to indicate that the angle is 425 degrees instead of 65" is the word COTERMINAL. Mathematically we would say a 425 degree rotation is coterminal with a 65 degree rotation, and both are coterminal with a negative 295 degree rotation. Although I would not say a 425 degree angle is "acute," I would say it had an acute "reference angle." The purpose of the language is to help us understand the things which are alike, and those which are different, so to me, it wouldn't be accurate to just say a 425 degree angle is acute. Hope this helps. - Doctor Pat, The Math Forum
Tuesday, September 8, 2009
[Scribe Post]...[Kharon B]...[Chapter 3]
Great Debate -PoP
Monday, September 7, 2009
Scribe Post 9/4 Chapter 2
Thursday, September 3, 2009
Scribe Post, Jericho, Chapter 2
In Class Conversion Examples..
Tuesday, September 1, 2009
Scribe Post
First off, we had our daily quiz, which consisted of plotting lines and line segments. The answers to the quiz have already been posted on the blog. After that, Jojo reminded us about significant contributions (on our pbworks) which should be done by the end of this unit (chapters 1-3 in our Essential Geometry book).
During the next part of class, we focused on our homework from the night before. First, we took three problems that people had trouble on (10.C, 14, 22), and put their numbers up on the board. Next, Jojo slit the class into three groups, an then assigned each group a problem. The groups then solved the equations while showing every step. Then we switched problems and checked over them to see if the other group had it right.
Lastly, Jojo went over conversions again. He went on to remind u that the conversion factor that we NEED TO KNOW for the test is the conversion from inches to centimeters (2.54 cm to every 1in).
That basically sums up the class. I am open to any critiques that anybody has. I will see everyone tommorow.
The next scribe is Christian. Sorry budddy, but believe me, you'll thank me for getting this out of the way early for you.
Fun with Angles
http://www.bbc.co.uk/schools/ks2bitesize/maths/activities/angles.shtml
Estimates & Measuring -PoP
* An estimate is not a guess.
* If you can measure, why estimate?
* Linear measurements are not useful in everyday life.
* Unless a measurement is exact, what good is it?
DQ2 Solution
Points A, B, C, and D are shown in the figure below. Alter the drawing, by sketching and labeling each of the following:
a.) line k[1], determined by points A and C
b.) DB
c.) line k[2], which contains D and is parallel to CB (sketch best you can and use parrallel symbol to denote)
d.) Y, which is the intersection of k[1] and k[2]
e.) Z, where Z is the midpoint of DY
(use an equation that suggests Z is a midpoint)