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Tuesday, November 10, 2009

Andrew, Scribe Post, Chapter 8

In class we have started learning about the Pathagorian Theorm (A)^2+(B)^2=(C)^2 or (Leg1)^2+(Leg2)^2=(Hypotenuse)^2




We also began talking about Right Triangles and in class we learned some special right triangles.  We learened the 30-60-90 triangle and the 45-45-90 triangle.  These two triangles have side lengths whose ratios will always stay the same and make it easy for us to solve for missing side lengths.


                                                                               30-60-90 triangle
                                                                     45-45-90 triangle
Using these special triangles we can take the proportions of the sides to find the side lengths of similar figures and we can use the proportions to find missing side lengths.
This is a very useful tool and all you have to remember is:
30-60-90 triangles 
leg=1
leg=square root of 3
hypotenuse=2
45-45-90 triangles
leg=1
leg=1
hypotenuse=sqaure root of 2



We will have a test on November 16 on Chapter 8
The next scribe is Henry

1 comment:

  1. Also about that last helpful hint,
    obviously one way of using it is a proportion so let's say for, a 30-60-90 triangle:
    We know that the shorter leg is 5 inches and we need to find the hypotenuse. This is how you would solve it: 2/1=x/5. Then you would cross multiply and do all that, and get your answer of ten for x.
    2 is the hypotenuse, and 1 is the shorter leg. Of course with this triangle the trick is very easy, as all you really have to do is multiply the shorter leg by two.

    Sorry if this comment was completely unhelpful, just trying to help put it in context (?) I guess...

    ReplyDelete

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